已知全集U={0,1,2,3,4},*A={0,1,3},B={0,1,4},则(∁UA)∪B为(  )  ...

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已知全集U={0,1,2,3,4},*A={0,1,3},B={0,1,4},则(∁UA)∪B为(  )  ...

已知全集U={0,1,2,3,4},*A={0,1,3},B={0,1,4},则(∁UA)∪B为(  )           

A.{0,1,2,4}     B.{0,1,3,4}     C.{2,4}           D.{4}

                                                          

【回答】

A

【考点】交、并、补集的混合运算.                               

【专题】*.                                              

【分析】由全集U={0,1,2,3,4},*A={0,1,3}先求出CUA={2,4},再由B={0,1,4},能求出(CUA)∪B.                                          

【解答】解:∵U={0,1,2,3,4},*A={0,1,3},                 

∴CUA={2,4},                                              

∵B={0,1,4},                                             

∴(CUA)∪B={0,1,2,4}.                                    

故选:A.                                                   

【点评】本题考查*的交、交、补集的混合运算,是基础题.解题时要认真审题,仔细解答.           

知识点:*与函数的概念

题型:选择题

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